00:01
Yeah, so hello everyone.
00:02
In the question, we have given a figure in which we have provided a battery of 120 volts.
00:16
Circuit has a capacitor, ca, of 4 micro -ferred, which has for the branching of a capacitor, let's say, cb, which is equals to 2 micro -ferrets.
00:35
There are also two capacitors of v3 and v4 there.
00:48
This is plus and this is minus side.
00:55
This capacitor is c, let's say, of 6 micro -farrad and this is let's say cd of 3 micro -faird.
01:06
So also resolving this circuit will get a new circuit of 120 volts battery.
01:13
This is 4 micro -faird.
01:19
Here it has a for the branching of a capacitor.
01:26
Let's say this is c1 is equals to 2 micro -faird and this is also 2 micro -farrid.
01:38
Again after resolving this we'll get a circuit of a battery which is 120 volts.
01:46
Let's say we draw partition here.
01:49
This is 4 micro -faird and this is 4 microferred to c1.
02:06
1 is equal to 6 multiplied by 3 divided by 6 plus 3.
02:12
This comes out to the 18 divided by 9, which is equal to 2 micro -farrad.
02:19
Hence we calculate from here c1 and c2 is equal to 2 plus 2 is equal to 4 microferrette.
02:28
Vl is equal to 60 volts and v2 is equal to 4 divided by 4 plus 4.
02:43
Multiplied by 120 is equal to 60 volts.
02:50
Now the energy stored in each capacitor is c .a equals to 1 divided by 2 multiplied by c .a.
03:09
Van square which is equal to 1 divided by 2 multiplied by 4 multiplied by 10 raised to the power minus 6 multiplied by 60 to the power 2...