Question

5. (a) (5 points] Assume that Moose Elk heights are normally distributed with a mean given by µ = 93 inches, and a standard deviation given by ? = 3.5 inches. If 1 Moose Elk is randomly selected, then the probability that its height is GREATER than 94 inches is approximately (i) 0.3875 (ii) 0.9992 (iii) 0.0008 (iv) 0.6125 Sketch: (b) [5 points] Refer to Part (a). If 121 Moose Elk are randomly selected, then the probability that they have a mean height GREATER than 94 inches is approximately (i) 0.3875 (ii) 0.9992 (iii) 0.0008 (iv) 0.6125 Sketch:

          5. (a) (5 points] Assume that Moose Elk heights are normally distributed with a mean given by µ = 93 inches, and a standard deviation given by ? = 3.5 inches. If 1 Moose Elk is randomly selected, then the probability that its height is GREATER than 94 inches is approximately
(i) 0.3875
(ii) 0.9992
(iii) 0.0008
(iv) 0.6125
Sketch:
(b) [5 points] Refer to Part (a). If 121 Moose Elk are randomly selected, then the probability that they have a mean height GREATER than 94 inches is approximately
(i) 0.3875
(ii) 0.9992
(iii) 0.0008
(iv) 0.6125
Sketch:

5. (a) (5 points] Assume that Moose Elk heights are normally distributed with a mean given by µ = 93 inches, and a standard deviation given by ? = 3.5 inches. If 1 Moose Elk is randomly selected, then the probability that its height is GREATER than 94 inches is approximately
(i) 0.3875
(ii) 0.9992
(iii) 0.0008
(iv) 0.6125
Sketch:
(b) [5 points] Refer to Part (a). If 121 Moose Elk are randomly selected, then the probability that they have a mean height GREATER than 94 inches is approximately
(i) 0.3875
(ii) 0.9992
(iii) 0.0008
(iv) 0.6125
Sketch:

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