6 12 points two solid aluminum shafts g 27 gpa are connected...

Name: 6 12 points two solid aluminum shafts g 27 gpa are connected to a coupling disk b and to fixed supports at a and c for the loading shown identify which shaft has the largest shearing stress 69586
Uploaded: 2022-04-14T11:29:13-08:00
Duration: 10 min 17 s
Channel: Shaiju T
Description: 6 12 points two solid aluminum shafts g 27 gpa are connected to a coupling disk b and to fixed supports at a and c for the loading shown identify which shaft has the largest shearing stress 69586

6. (12 Points) Two solid aluminum shafts (G = 27 GPa) are connected to a coupling disk B and to fixed supports at A and C. For the loading shown, identify which shaft has the largest shearing stress and what the magnitude of that shearing stress is. 200 mm 300 mm C B 40 mm 2.2 kN-m 40 mm

Transcript

00:01 Hello students i am a teacher for this question so this question two solid steel softs means two softs are given one is 50 m m and second is 38 m they are connecting to a coupling they are connecting to a cutting the b portion is the coupling so in the first if we talk about the soft ab soft a so in the soft ab the tension t is equal to t ab and the l ab is equal to the lab is is equal to the equation is given 200 m m is 0 .2 mm and the c is equal to the central is equal to 1 .2 d and which is equal to 25 mm sorry c is the radius of the sub and it is equal to 0 .025 meter and after that the jav which is equals to pi by 2 c the power 4 which is equal to pi by 2 multiply 0 .025 the power 4 and it is equal to 613 .59 multiply 10xm the power 9 meter the power 4 so the value of j a b is equal to 613 .59 multiply 10x the power minus 9 and the value of qb which is equal to tab multiply l ab divided by q multiply j so it is equal to it is so after solving this the value of t a b tension at ab is equal to g multiply j a b divided by l a b multiply q b so put the values here the value of g is equal to 7 7 .2 multiply ten as the power 9 which is given in our equation multiply the value of jab is equal to 613 .59 multiply 10 s the power minus 9 divided by the value of l ab is equal to 0 .200 and it is all to multiply by the qb.

02:08 So the value of tab is equal to 236 .847 multiply 10 sd power 3 qb.

02:18 So it is the value of tab.

02:20 Same for the soft bc.

02:24 The value of t is equal to tvc and the value of l bc which is given 0 or 2.

02:30 250 mm which is equal to 0 .250 m meter and the c is equal to half of the diameter which is equals to 19 mm and 0 .019 after that we find the value of j ab which is equal to pi by 2 c k power 4 which is equal to pi by 2 multiply the value of c is equal to 0 .019 t power 4 it is equals to 204 .71 multiply 10x the power minus k 9 later the power 4 so we find the value of t bc same formula which you use in the equation the previous part which is g multiply j tc divided by l bc multiply q bc multiply q b so put the values you are 77 .2 multiply 10 s the power 9 multiply 204 multiply 0 .7 multiplied 10 x0 .9 divide by the value of lvc is 0 .550 and it is also multiplied by the qb...

Question

6. (12 Points) Two solid aluminum shafts (G = 27 GPa) are connected to a coupling disk B and to fixed supports at A and C. For the loading shown, identify which shaft has the largest shearing stress and what the magnitude of that shearing stress is. 200 mm 300 mm C B 40 mm 2.2 kN-m 40 mm

Please give Ace some feedback