00:01
Hello, here we have to find the magnetic force vector which acts on the wire segment.
00:06
First of all, we have to find the direction of the x -axis, and x -axis is directed into the screen.
00:12
Therefore, vector b can be written as negative 0 .50, 0 -0 -tesla.
00:21
And vector i is 0, negative i sign of 30 degree, negative i x.
00:32
Cosine of 30 degree amperes.
00:35
That is 0, negative 1 .75, negative 3 .03, amperors.
00:45
Now we have to label each component as x, y, z, and the product which we have to calculate consists of part.
00:57
First, we have to calculate the vector product of i and b.
01:03
This vector product is also a vector.
01:05
And that is this can be calculated as following...