00:01
Here in this question we are given that that a plane is flying towards north but gradually it makes a sharp turn of 180 degrees.
00:12
Basically we are given the speed of the plane.
00:15
So the speed of the plane is given here that is equals to 403 .3 kilometer per hour and we are given that that the time taken to turn is given that from here is equals to 32 second.
00:37
So this is the speed and the time which we are given for that.
00:40
So now we have to find out the value of the centripetal acceleration.
00:47
So here what we can say that that to calculate the distance traveling during the turn as we know that distance is equals to the speed multiplied by the time.
01:01
Here d is representing the distance, s is representing the speed and t is representing the time.
01:07
So as we are given the values from here we are given the value of the distance that is 403 .3 it is in kilometer per hour.
01:16
We can convert it into meter per second.
01:19
So for that firstly we have to divide this term with 1000 multiply with the 1000 and then we have to divide it with the it is in hour and 1 hour is equals to the 3600 second.
01:35
So divided by the 3600.
01:38
So from here we get the value of the speed.
01:41
So speed from here will become equals to 112 .02 meter per second.
01:49
So distance from here will become equals to 112 .02 meter per second multiplied by the time which is given to us that is equals to 32 seconds.
02:00
Solving this value from here we get the value of the distance that will become equals to 3584 .64 meter.
02:09
So this is the value of the distance.
02:11
Now for that we can say that this is basically the circumference of the path.
02:16
So the circumference from here is equals to 3584 .64 meter...