00:01
Hello everyone we have given a circuit of network 6.
00:03
The register connected in a series, register is connected in a series and parallel register are connected in series and parallel combination so this is r in the series combination and this is the parallel condition so we can calculate this and vt is given 12 volts.
00:31
The volume of the voltage is given 12 here.
00:37
R1, r2 and r3 in series combination.
00:44
This is in series combination.
00:47
So, and r4 and r5 also in series combination.
01:04
So, resistance is, r equivalent resistance is r1 plus r2 plus r3.
01:16
Then we get 1 plus 2 plus 3 resistance of r1 is 1 this is 2 and resistance of r 2 and resistor of r 3 is given in the problem so 1 plus 2 plus 1 is 6 om and the lower branch this is the upper branch in the lower branch resistance is r d is equals to r 4 plus r 5 then we get r 4 is 4 and this is 5 this is 9 ome resistance then r -dash and r double -dash, then r -dash and double r -dash in the parallel and r6 in series.
02:17
Then this is making r -dash and this is making r -double -dash.
02:26
So both r and r -dash is in parallel and the r6 is in the series...