Question

6 In Example 12.8, we found evidence of heteroskedasticity in $u$, in equation (12.47). Thus, we compute the heteroskedasticity-robust standard errors (in [ ]) along with the usual standard errors: $\overline{return}_t = .180 + .059 \, return_{t-1}$ $(.081) \quad (.038)$ $[.085] \quad [.069]$ n = 689, R^2 = .0035, \overline{R}^2 = .0020.$ What does using the heteroskedasticity-robust $t$ statistic do to the significance of $return_{t-1}$?

          6 In Example 12.8, we found evidence of heteroskedasticity in $u$, in equation (12.47). Thus, we compute the heteroskedasticity-robust standard errors (in [ ]) along with the usual standard errors:
$\overline{return}_t = .180 + .059 \, return_{t-1}$
$(.081) \quad (.038)$
$[.085] \quad [.069]$
n = 689, R^2 = .0035, \overline{R}^2 = .0020.$
What does using the heteroskedasticity-robust $t$ statistic do to the significance of $return_{t-1}$?

6 In Example 12.8, we found evidence of heteroskedasticity in u, in equation (12.47). Thus, we compute the heteroskedasticity-robust standard errors (in [ ]) along with the usual standard errors:
returnt = .180 + .059 returnt-1
(.081) (.038)
[.085] [.069]
n = 689, R^2 = .0035, R^2 = .0020.What does using the heteroskedasticity-robusttstatistic do to the significance ofreturnt-1?

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Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

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Solved by Expert Sri K

03/15/2023

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Heteroskedasticity means that the variance of the errors is not constant across all observations. Show more…

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6 In Example 12.8, we found evidence of heteroskedasticity in u, in equation (12.47). Thus, we compute the heteroskedasticity-robust standard errors (in []) along with the usual standard errors: $\widehat{return_t} = .180 + .059 return_{t-1}$ (.081) (.038) [.085] [.069] n = 689, $R^2$ = .0035, $\overline{R}^2$ = .0020. What does using the heteroskedasticity-robust t statistic do to the significance of $return_{t-1}$?