7. Consider particle A is surrounded by particle B, C, and D...

7. Consider particle A is surrounded by particle B, C, and D shown in the figure. The distance between particles is equal to 10 nm. $\theta_1 = \theta_2 = \theta_3 = 120^\circ$. Find the net force acting on particle A due to the other three and specify the direction (in terms of angle with respect to the positive x-axis) of the net force. (10 pts) C: +10 $\mu$C $\theta_3$ $\theta_1$ A: -11 $\mu$C $\theta_2$ B: -6 $\mu$C D: +5 $\mu$C

Transcript

00:03 In figure, figure is not given, but we can understand the situation by reading this statement.

00:10 Three positively charged particles are fixed on x -axis.

00:14 So given that three positive charge are fixed on x -axis, that this is a, b and c.

00:23 So these are three charges.

00:25 All three are positive.

00:27 And particle b and c are so close to each other that they can be considered at the same.

00:33 From the particle a.

00:35 So given that both of these are so much close, both of these b and c are so much close, we can take the distance of both of them from a is fixed.

00:44 Let us take that distance is x.

00:46 So a, b is equal to x and a c is also equal to x.

00:52 And again, the net force of particle a due to particle b and c is 2 .014 into 10 to the power minus.

01:05 3 newton.

01:06 So in this situation, the net force on particle a due to b and c is 2 .014 into 10 to the power minus 23 newton.

01:15 And that is in the negative direction of x -axis.

01:18 So let us write in this situation, the force on a due to b and c is equal to that is the net force.

01:26 So that will be 2 .014 into 10 to the power minus 23 newton.

01:33 And other cases, particle b is move to the opposite side of a.

01:41 So in other situation what they are doing, they just move that particle.

01:49 Sorry, this is particle a.

01:51 They move just particle b to the opposite.

01:55 So this is particle b and this is particle c.

01:59 This is a new situation now and the distance is same...

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