00:01
In this question, we are asked to calculate the vapor pressure of the solution and we are having two components here.
00:06
So, first component is acetonitrile which can be written as such.
00:12
Now, the second component is acetone.
00:15
So, we are having the values of vapor pressure of acetone as well as the acetonitrile.
00:22
So, let us write those values over here.
00:24
So the vapor pressure of acetone nitrile is equals to 81 .0 and then it will be here tor.
00:32
Now we can say that the vapor pressure of acetone will be here equals to it is going to be here we can say 184 .5 and then it will be here tor.
00:45
So solving this very problem we can say that moles of acetoneitrile will be equals to it is 0 point and then here it is 550 now the moles of acetone will be equals to 0 .350 moles and hence we can say that the value of xa that is mole fraction of acetoneitrile is na divided by it will be na and then here it is plus nb.
01:17
So from this information we can write here that the value of xa that is mole fraction of acetoneitribe is 0 point and then here it is going to be 550 divided by it will be 0 .550 plus it is here 0 .350 and hence we can say that the value of xa that is mole fraction of a will be equal to 0 .6 and here it is 1 ,1.
01:50
Now the value of xb that is mole fraction of b will be equal to number of moles of b divided by it will be here total number of moles and hence we can say that the value of mole fraction of acetone will be here 0...