00:01
Now, solution of this question given the shortcoming tree and expecting essential occasion d, e, f and g are free occasion that suggest middle of the road occasion b and c whose convergence is high level occasion and are likewise theory.
00:21
It is known as free occasion.
00:22
It is known as free occasion.
00:27
Free occasion a and b, a and b, p a, p a, convergence b, a, convergence b, convergence b or p and b, a and b.
00:44
This is equal to p a, p b.
00:49
So, p a association, association b, p a association b or p a, b, p a or b.
01:00
This is equal to p a plus p b minus p a, p b, p a, p b.
01:12
Subsequently, p of b is equal to p d or e, p d or e.
01:19
So, this is equal to p d plus p e minus p d, p e.
01:28
So, this is equal to 10 to the power, 10 to the power minus 2 plus 10 to the power minus 3 plus 10 to the power minus 2 multiply 10 to the power minus 3.
01:40
This is equal to 1 .099 multiply 10 to the power minus 2...