a 0.26kg rock is thrown vertically upward from the top of a cliff that is 15m high. when it hits the ground at the base of the cliff the rock has a speed of 29m/s. assuming that air resistance can be ignored find the initial speed of the rock
Added by Karen F.
Step 1
This total energy is the sum of the kinetic energy (due to its speed) and the potential energy (due to its height above the ground). The kinetic energy (KE) is given by the formula KE = 0.5 * m * v^2, where m is the mass of the rock and v is its speed. Show more…
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