A 0.54 mm diameter circular hole is illuminated by light of wavelength 443 nm. What is the width of the central maximum on a screen located 2.86 m behind the slit? Provide your answer in millimeters.
Added by Monica H.
Step 1
The angular size of the central maximum can be calculated using the formula: θ = 1.22 * (λ / d) where: θ = angular size of the central maximum λ = wavelength of light = 443 nm = 443 * 10^-9 m d = diameter of the circular hole = 0.54 mm = 0.54 * 10^-3 m θ = 1.22 * Show more…
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