A 54-kg ice skater pushes off the wall of the rink, giving herself an initial speed of 2.5 m/s . She then coasts with no further effort. The frictional coefficient between skates and ice is 0.025. How far does she go?
Added by Soph D.
Step 1
First, we need to calculate the initial kinetic energy of the skater. The formula for kinetic energy is 1/2 * mass * velocity^2. Substituting the given values, we get 1/2 * 54 kg * (2.5 m/s)^2 = 168.75 Joules. Show more…
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