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1. [-/0.58 Points] DETAILS SWOKPRECALC13 5.1.003. MY NOTES ASK YOUR TEACHER PRACTICE A If the given angle is in standard position, find two positive coterminal angles and two negative coterminal angles. (Enter your answers as a comma-separated list.) (a) $670^\circ$ positive angles 40, 400 negative angles -310, -660 (b) $\frac{5\pi}{6}$ positive angles $\frac{17\pi}{6}$, $\frac{29\pi}{6}$ negative angles (c) $-\frac{\pi}{5}$ positive angles negative angles Need Help? Read It

          1. [-/0.58 Points]
DETAILS
SWOKPRECALC13 5.1.003.
MY NOTES
ASK YOUR TEACHER
PRACTICE A
If the given angle is in standard position, find two positive coterminal angles and two negative coterminal angles. (Enter your answers as a comma-separated list.)
(a) $670^\circ$
positive angles 40, 400
negative angles -310, -660
(b) $\frac{5\pi}{6}$
positive angles $\frac{17\pi}{6}$, $\frac{29\pi}{6}$
negative angles
(c) $-\frac{\pi}{5}$
positive angles
negative angles
Need Help? Read It
        
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1. [-/0.58 Points]
DETAILS
SWOKPRECALC13 5.1.003.
MY NOTES
ASK YOUR TEACHER
PRACTICE A
If the given angle is in standard position, find two positive coterminal angles and two negative coterminal angles. (Enter your answers as a comma-separated list.)
(a) 670^∘
positive angles 40, 400
negative angles -310, -660
(b) (5π)/(6)
positive angles (17π)/(6), (29π)/(6)
negative angles
(c) -(π)/(5)
positive angles
negative angles
Need Help? Read It

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Precalculus with Limits
Precalculus with Limits
Ron Larson 2nd Edition
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(a) 670° positive angles: 40°, 400° negative angles: -310°, -660° (b) ( frac{5pi}{6} ) positive angles negative angles (c) ( -frac{pi}{5} ) positive angles negative angles
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Transcript

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00:01 I'm going to quickly jump into this just because there's so many problems to do that you 140 degrees are going counterclockwise and you're going to end up in quadrant two because that's before 180 degrees will be to the left.
00:16 Now with negative 150 you're going clockwise.
00:20 Negative 150 degrees and that puts me in quadrant three and then the next one, 2 pi over 3 is ending up in quadrant two as well.
00:41 So moving on to the next group where you have to figure out the co -terminal.
00:48 Basically, you just have to know that co -terminal means you're either going to add 360 to it or you're going to subtract 360 because you want to have the same ending.
00:58 So i'm just going to use a calculator just to make sure i'm not crazy that i have 480 degrees as well as 120 minus 360 is negative 240 degrees.
01:13 And i could do the same thing with that negative 10 degrees is i can add 360 to this.
01:19 I don't need a calculator for that one.
01:21 That's 350 degrees and negative 10 minus 360 would give me negative 370.
01:29 And then the next one, it's still co -terminal, but this time you're doing 2 pi over 3.
01:40 And what i would do, i'm adding 2.
01:42 To it, but i would actually make it 6 pi over 3 because that's equal to 2 pi.
01:48 So 8 pi over 3, and then i also need to subtract 2 pi and that gives me negative 4 pi over 3.
02:01 So i'm going to do the same thing with negative 3 pi over 4.
02:05 But think about if you're trying to add 2 pi with a denominator of 4, you might do 8 pi over 4, but then i'm also going to do minus 8 pi over 4.
02:16 So this time i get 5 pi over 4 and negative 11 pi over 4.
02:25 Now converting degrees to radiance, what i just tell students to do is to multiply by a half pi and divide by 180.
02:35 I think that's all you need.
02:37 So i would use a calculator and figure out 150 over 180 reduces to 5 over 6...
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