A body having a rotational inertia of 0.17 kg m^2 and rotating with a velocity of 3.67 rad/s has a rotational kinetic energy of ____ J (answer needs to be with 2 decimal places and in units of joule)
Added by Mandy Y.
Step 1
17 kg m^2) and ω is the angular velocity (3.67 rad/s). Now, we can plug in the values and calculate the rotational kinetic energy: K = 1/2 * 0.17 kg m^2 * (3.67 rad/s)^2 Show more…
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