A buffer solution is prepared by combining 150.0.0 mL of a 0.475 M solution of CH3NH2 with 50.00 mL of a 0.175 M solution of CH3NH3Cl Find the pH of the buffer solution. (Do not forget to first find concentrations in the mixture when the 2 solutions are combined.)
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Step 1
- For CH3NH2: Moles = Molarity × Volume = 0.475 M × 150.0 mL = 0.475 mol/L × 0.150 L = 0.07125 mol - For CH3NH3Cl: Moles = Molarity × Volume = 0.175 M × 50.00 mL = 0.175 mol/L × 0.050 L = 0.00875 mol Show more…
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