A cord of mass 1.56 x 10-2 kg is stretched between two supports A and B 3.46 m apart. If the tension in the cord is 2.71 x 1011N. How long will it take a pulse to travel from A to B and then back to A?
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Step 1
Given: Mass of the cord (m) = 1.56 x 10^-2 kg Length of the cord (L) = 3.46 m Mass per unit length (μ) = m / L μ = 1.56 x 10^-2 kg / 3.46 m μ = 4.52 x 10^-3 kg/m Show more…
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