A description of a line is given. Find an equation for the line in general form. The line that passes through the point (1,7) and is perpendicular to the line x - 3y + 16 = 0.
Added by Michelle R.
Step 1
We can rearrange the equation x-3y+16=0 to solve for y in terms of x: x-3y+16=0 -3y=-x-16 y=(1/3)x+(16/3) So the slope of this line is 1/3. Show more…
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