A distribution of values is normal with a mean of 54.2 and a standard deviation of 16.1. Find the probability that a randomly selected value is less than 96.1. P(X < 96.1) = Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
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1 using the formula z = (X - μ) / σ, where X is the value, μ is the mean, and σ is the standard deviation. z = (96.1 - 54.2) / 16.1 z = 41.9 / 16.1 z ≈ 2.6037 Show more…
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