00:01
Now solve this equation given that y is equal to at x square.
00:10
We need to find the point this curve closer to point 0 ,1.
00:24
Now all point on the curve will be the form of form of x at x square.
00:32
If d is the distance from x, y to the y to the point 0 ,1 so d square.
00:45
So d square is equal to x minus 0 square plus at x square minus 1 to the whole square.
00:54
Now d square is equal to x square plus at x square to the power whole square plus 1 square minus 2 at x square.
01:06
Here d square is equal to 64 to the power x to the power 4 minus 15 x square plus 1.
01:13
So d is equal to under root of 64 x to the power 4 minus 15 x square plus 1.
01:22
As we looking for closer point so we need to minimize d.
01:27
So differentiate of d to d dash is equal to 64 4 x cube minus 15 2 x.
01:36
So d dash is equal to 2 x 64 2 x square minus 15 bracket is divided by 2 d is 2 d.
01:49
Now d dash is equal to x divided by d bracket 128 x square minus 15.
01:57
Now d dash is equal to x divided by under root of 64 x to the power 4 minus 15 x square plus 1.
02:06
Now if d is minimum d dash is equal to 0.
02:10
Now x divided by root 64 x to the power 4 minus 15 x square plus 1 128 x square minus 15 is equal to 0...