A Food Marketing Institute found that 30% of households spend more than $125 a week on groceries. Assume the population proportion is 0.3 and a simple random sample of 180 households is selected from the population. What is the probability that the sample proportion of households spending more than $125 a week is between 0.22 and 0.48? Answer = (Enter your answer as a number accurate to 4 decimal places.)
Added by Miguel M.
Step 1
- Population proportion, \( p = 0.3 \) - Sample size, \( n = 180 \) - We want \( P(0.22 < \hat{p} < 0.48) \), where \( \hat{p} \) is the sample proportion. Show more…
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