5) A fraction nonconforming control chart with $n = 350$ has the following parameters: UCL = 0.0969 Center Line = 0.0500 LCL = 0.0031 a) Find the width of the control limits in standard deviation units. b) Suppose the process fraction nonconforming shifts to 0.12. What is the probability of detecting the shift on the first subsequent sample?
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The width of the control limits in standard deviation units is given by: Width = (UCL - LCL) / (3 * sqrt(p * (1-p) / n)) where: UCL = Upper Control Limit LCL = Lower Control Limit p = Centerline value n = sample size Given: UCL = 0.0969 Centerline = 0.0500 LCL = Show more…
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