Question

a. $f(x) = 3x^2 - 11x - 8$ exact values (use square roots): $x = $ approximate values (round to two decimal places): $x = -0.621, 4.288$ b. $g(x) = 3x^2 + 11x - 6$ exact values (use square roots): $x = $ approximate values (round to two decimal places): $x = -0.621, 4.288$

Name: a fx 3x2 11x 8 exact values use square roots x approximate values round to two decimal places x 0621 4288 b gx 3x2 11x 6 exact values use square roots x approximate values round to two decim 40584
Uploaded: 2024-07-15T23:59:10-08:00
Duration: 1 min 11 s
Channel: Andrew Noble
Description: a fx 3x2 11x 8 exact values use square roots x approximate values round to two decimal places x 0621 4288 b gx 3x2 11x 6 exact values use square roots x approximate values round to two decim 40584

          a. $f(x) = 3x^2 - 11x - 8$
exact values (use square roots): $x = $
approximate values (round to two decimal places): $x = -0.621, 4.288$
b. $g(x) = 3x^2 + 11x - 6$
exact values (use square roots): $x = $
approximate values (round to two decimal places): $x = -0.621, 4.288$

a fx 3x2 11x 8 exact values use square roots x approximate values round to two decimal places x 0621 4288 b gx 3x2 11x 6 exact values use square roots x approximate values round to two decim 40584

Added by Mohamed C.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Andrew Noble

07/15/2024

Step 1

Using the quadratic formula, we have: $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ where $a = 3$, $b = -11$, and $c = -8$. $x = \frac{11 \pm \sqrt{(-11)^2 - 4(3)(-8)}}{2(3)}$ $x = \frac{11 \pm \sqrt{121 + 96}}{6}$ $x = \frac{11 \pm \sqrt{217}}{6}$ The exact values are Show more…

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a. $f(x) = 3x^2 - 11x - 8$ exact values (use square roots): $x = $ approximate values (round to two decimal places): $x = -0.621, 4.288$ b. $g(x) = 3x^2 + 11x - 6$ exact values (use square roots): $x = $ approximate values (round to two decimal places): $x = -0.621, 4.288$