A liquid is flowing in a horizontal uniform capillary tube under a constant pressure difference P. The value of pressure for which the rate of flow of the liquid is doubled when the radius and length both are doubled is
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Mathematically, it can be expressed as: Q = πPr^4 / 8ηl where η is the viscosity of the liquid. Given that the rate of flow is doubled when the radius and length are both doubled, we can write: 2Q = πP(2r)^4 / 8η(2l) Simplifying this gives: 2Q = 16πPr^4 / Show more…
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