00:01
To calculate the mass of each phosphorus oxide, we need a balanced chemical reaction.
00:05
Phosphorus reacts with oxygen, producing p406 and p410.
00:11
To balance it, we need eight phosphorus and eight oh -2s.
00:14
That then gives us eight phosphorus and 16 oxygens on both sides.
00:21
So if we have 158 .7 grams phosphorus, we can divide by the molar mass phosphorus to get moles phosphorus, and then go from moles phosphorus to moles p406 with the 8 to 1 mole relationship.
00:35
And last of all, multiply by the molar mass p406, and we get 140 .8 grams p406.
00:45
Let's then add, let's then see how many grams of p406 the 164 grams of o2 can produce in order to identify the limiting reactant and what the true theoretical yield is.
00:58
We'll divide the grams oxygen by the molar mass oxygen to get moles oxygen, and then moles oxygen to moles p406, with the 8 to 1 molar relationship, and then multiplied by the molar mass p406.
01:13
And we get essentially the same, 140 .9 grams, p406...