A pelton wheel is supplied with 180 litressec of water under...

Name: a pelton wheel is supplied with 180 litressec of water under a head of 300 m the mean peripheral velocity of the bucket is 20 ms if the outlet tip angle of the bucket is 160 find out the pow 43267
Uploaded: 2023-05-25T16:51:17-08:00
Duration: 7 min 15 s
Channel: Prabhat Tyagi
Description: a pelton wheel is supplied with 180 litressec of water under a head of 300 m the mean peripheral velocity of the bucket is 20 ms if the outlet tip angle of the bucket is 160 find out the pow 43267

A pelton wheel is supplied with 180 litres/sec, of water under a head of 300 m. The mean peripheral velocity of the bucket is 20 m/s. If the outlet tip angle of the bucket is 160°, find out the power developed and efficiency .

Transcript

00:01 Here in this question we have given pelton wheel diameter equals to 2 meter.

00:23 Also we have the power equals to 500 kilowatt.

00:34 We have speed equals to 180 rpm.

00:44 Now we calculate the angular velocity by using the relation omega equals to 2 multiplied by pi multiplied by n divided by 60.

00:57 Here omega is the angular velocity and n is the number of revolution in a minute.

01:03 So now on substituting the value we get omega equals to 2 multiplied by pi multiplied by 180 divided by 60.

01:13 So now on simplifying we get omega equals to 18 .85 radian per second.

01:22 Now we are going to calculate the force in the shaft by using the formula that is w of s equals to t multiplied by omega.

01:36 We can consider this as equation number first.

01:39 Here w of s is the power of the shaft and t is the torque produced.

01:44 So we know that the torque produced is given by t equals to f multiplied by d divided by 2.

01:59 Here f is the force produced and d is the diameter of the pelton wheel.

02:03 So we substitute 2 meter for d.

02:11 So we get t equals to f multiplied by 2 divided by 2.

02:16 So from above we get t equals to f.

02:22 Now here we substitute f for t and 500 multiplied by 10 to the power 3 watt for w of s and 18 .85 radian per second for omega in equation first.

02:43 Therefore we get 500 multiplied by 10 to the power 3.

02:49 Actually we just convert this from kilowatt to watt equals to f multiplied by 18 .85.

03:00 Now on simplifying this in terms of f we get f equals to 26526 newton...

Question

A pelton wheel is supplied with 180 litres/sec, of water under a head of 300 m. The mean peripheral velocity of the bucket is 20 m/s. If the outlet tip angle of the bucket is 160°, find out the power developed and efficiency .

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