00:01
Now in this question, you ask you to construct a 95 % confidence in a level for the population, for the proportion of the population, use at least one prescription medication rate.
00:16
So the survey has a sample of, i'm going to call it n, which is 3 .7, maybe a better, has a sample size n equals to 3 ,000 and 5 adults.
00:32
And it was found that the proportion of the, i mean, the sample mean, right, the sample proportion, actually, of this adults, how use at least one prescription, medication is at 2%, right? so i'm not going to call it p, and actually i'm going to call it sample mean, okay, sample also a sample proportion.
00:59
And then you ask a few questions, the first question is how many people use at least one prescription and medication rate.
01:06
So i think that's roughly m times expire, right? so that's given by 3 .005 times 80 % and they find the margin error right for the actual population proportion rate.
01:22
The margin error of course is given by the z score correspond to the 95 complete level, which actually is g at 2 .5 % and then times the standard deviation, which is given by 82%.
01:35
Times 1 minus 82%, so it's 18%, and divided by the sample size, which is 0 ,0005, and take a square root.
01:48
And that's the margin of error...