A projectile is launched off an 80 foot high tower and reaches a peak height of 144 feet after 4 seconds. a. Write an equation to find the height of the projectile at any given time. Define any variables you use.
Added by Cindy W.
Step 1
Step 1: Let's define the variables we will use: h = height of the projectile at any given time (in feet) t = time in seconds g = acceleration due to gravity (approximately 32 feet per second squared) Show more…
Show all steps
Close
Your feedback will help us improve your experience
Erika Bustos and 53 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The height of a projectile fired vertically into the air (neglecting air resistance) at an initial velocity of 64 feet per second is a function of the time $(t)$ and is given by the equation $$ h(t)=64 t-16 t^{2} $$ Compute $h(1), h(2), h(3),$ and $h(4)$.
Functions
Relations and Functions
The height in feet of a projectile launched vertically from the ground with an initial velocity of 128 feet per second is given by the function $h(t)=-16 r+128 t,$ where $t$ is in seconds. Calculate and interpret the following. $$ h(4) $$
Polynomials and Their Operations
Introduction to Polynomials
A projectile is launched straight up from the top of a 144-ft building with an initial vertical velocity of 128 ft/sec. How long will it take the projectile to reach the ground?
Madhur L.
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD