Question

A proton accelerates along the line joining the two charges of a dipole, away from the dipole. The dipole is made up of two charges, both 60 nC in magnitude, separated by 0.5mm. What is the proton’s speed when it is 1cm away? 

          A proton accelerates along the line joining the two charges of a dipole,
away from the dipole. The dipole is made up of two charges, both 60 nC
in magnitude, separated by 0.5mm. What is the proton’s speed when it
is 1cm away?

Added by Jennifer A.

University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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A proton accelerates along the line joining the two charges of a dipole, away from the dipole. The dipole is made up of two charges, both 60 nC in magnitude, separated by 0.5mm. What is the proton’s speed when it is 1cm away?
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Transcript

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00:01 Hello students in the part of the question we have to find the direction of the electric field and the electric force so the direction of electric field direction electric field is from left to right left to right as you can see in this figure the direction is from left to right now the direction of electric force direction of electric force is same as the same as the direction of the same as the direction of electric field electric field that is from left to right itself left to right now in the part of the question we are asked to define electric dipole and electric dipole moment electric dipole electric dipole is a separation is a separation of positive and negative charges positive and negative charges for example a positive charge placed here and a negative charge which is placed here which is at a distance r.
01:41 So this is basically an electric dipole so the electric dipole moment is electric dipole moment is the product of is the product of magnitude of magnitude of charge and the distance between and distance between centers of positive and negative and negative charges that is it can be represented as nu where nu is the electric dipole moment nu is equal to the charge q into r where r is a separation between the centers of the positive and negative charges now coming to the c part of the question the dipole moment nu is given which is equal to 1 .75 and we have to find the separation between the two charges that is given by nu is equal to q into r now substituting the values 1 .75 is equal to q that is 1 .6 into 10 raised to minus 19 into the separation that is r therefore r is equal to 1 .75 divided by 1 .6 into 10 raised to minus 19 and this is equal to 1 .0937 into 10 raised to 19 into so this is the separation, but we have to find the separation in nanometers that is r is equal to 1 .0937 into 10 raised to 19 into 10 raised to minus 9 into 10 raised to minus 9 and therefore this is equal to 1 .09 into 10 raised to 28 nano meters, so this is the separation...
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