Question

A random sample of 45 internet videos is selected from a large library where the average length is 14 minutes with a standard deviation of 3.3 minutes. How likely is it for the sample mean to be between 15 and 20 minutes? Round to 3 decimal places.

          A random sample of 45 internet videos is selected from a large library where the average length is 14 minutes with a standard deviation of 3.3 minutes. How likely is it for the sample mean to be between 15 and 20 minutes? Round to 3 decimal places.
        
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Elementary Statistics a Step by Step Approach
Elementary Statistics a Step by Step Approach
Allan G. Bluman 9th Edition
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A random sample of 45 internet videos is selected from a large library where the average length is 14 minutes with a standard deviation of 3.3 minutes. How likely is it for the sample mean to be between 15 and 20 minutes? Round to 3 decimal places.
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Transcript

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00:01 There is given a mean and the standard deviation here.
00:03 So the average video length, which is the population mean denoted by mu that was given as 15 .4 and the population deviation means the population standard deviation which is given as 1 .6 here so the sample size given here, which is the sample size is 16 here so first of all, we have to find the probability for the sample.
00:26 So what i need i need the sample mean the sample mean is the same with the population mean which is 15 .4 and also i need the sample standard deviation sample standard deviation, which is the population standard division divided by square root of the sample size so the population the sample standard division, which is 1 .6 divided by root 16 that would be 0 .4 here so i can define the random variable x bar for the sample normally distributed the mean is 15 .4 in the standard division 0 .4 here so this is shorter than if this is shorter than 15 we have to find this probability here at this step i'm gonna use the normal cdf function there is no in a lower boundary put very small number upper boundary is 15 and the mean is 15 .4 and the standard division 0 .4 press second variance and the normal cdf lower boundary this is negative 1 second a99 and the upper boundary is 15 and the mean is 15 .4 in the standard division 0 .4 here so the answer would be which is 0 .15 and 87 here and the next part of the question if you just select a single video, right? so we have to use the population random variable x here which is normally distributed the mean and the standard division here so in this case, we're gonna find shorter than so the x is shorter than 15...
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