00:01
Hello, in this question we are required to calculate the discharge over.
00:06
In the first part, it is a triangular node with theta is equal to 60 degree.
00:11
And in the second part, a rectangular notch for which the width is 1 .5 meter.
00:19
Okay? so, for a triangular node, the discharge is given by q can be written for a triangular node's is equal to 8 over 15.
00:35
Cd into tangent theta by 2 theta or given to us is 60 degree under root 2g into h to the power 5 by okay this is the formula for a triangular nodes let me write it here triangular okay and for rectangular notes let me first write formula for both of this okay so for rectangular notes this value is this formula is 2 by 3 q can be written as 2 by 3 cd into l into under root 2g into h to the power 3 by 2 okay so now we will calculate the value for that first 4 triangular over here h is given to us h is equal to 22 centimeters that means h is 0 .22 meters theta is 60 degree and cd is also given to us that is equal to 0 .625.
02:11
Okay, so let me put all the values over here 8 by 15 into 0 .625 into tangent 60 by 2 means tangent 30 into under root 2 into 9 .81 into 0 .2 to the power 2 2 .5.
02:40
So when i calculate this value, it would be coming out to be, let me calculate this 8 over 15 into 0 .6 to 5 into tangent 30 degree into and root 2 into 9 .81 multiplied by 0 .2 to the power 2 .2 to the power 2 .5.
03:03
This value is coming out to be 0 .01935 meter cube per second.
03:12
Okay, because all the units that we put are in standard values.
03:17
Okay.
03:18
So our value of the cube would be in meter cube per second...