A researcher uses a microscope with a convex lens to view a...

Name: a researcher uses a microscope with a convex lens to view a sample the distance from the sample to the lens is 5 cm and the distance from the lens to the retina is 20 cm if the distance from 53082
Uploaded: 2021-08-26T17:41:02-08:00
Duration: 6 min 43 s
Channel: Vishal Gupta
Description: a researcher uses a microscope with a convex lens to view a sample the distance from the sample to the lens is 5 cm and the distance from the lens to the retina is 20 cm if the distance from 53082

A researcher uses a microscope with a convex lens to view a sample. The distance from the sample to the lens is 5 cm, and the distance from the lens to the retina is 20 cm. If the distance from the sample to the lens increases by 15 cm, the image is now focused:

Transcript

00:01 Hi, in this given problem there is a compound microscope in which focal length of objective lens is given as plus 0 .50 centimeter and focal length of ips that is given as plus 2 .0 centimeter.

00:39 Distance of object if we look for the objective lens an object has been kept at a distance of s -o -o 0 .52 centimeter in front of the objective lens focal length that is 0 .50 centimeter so using lens equation which is a relation among the image distance and here this image distance is for objective so it will be symbolized by s io plus one by object distance s o is equal to one by focal length f o now plugging in all known values here one by s io this is missing plus 1 by s .o which is 0 .52 centimeter is equal to focal length of object which is 0 .50 centimeter.

01:58 So this 1 by sio will be given by 1 by 0 .50 minus 1 by 0 .52.

02:10 Here lcm will be 0 .50 multiplied by 0 .50 multiplied by 0 .50.

02:16 And here it will be 0 .52 minus 0 .50 in numerator which will come out to be 0 .02 divided by 0 .50 multiplied by 0 .52.

02:35 So finally as i .o distance of image from the objective lens comes out to be 3rd 13 cm and this is positive means it is being formed towards right side of the objective lens now for the i piece it is being said that image is formed at a distance equal to least distance of distinct vision so distance of image as i for i piece that is 25 cm but as the image is virtual this is minus 25 centimeter towards the left side of the ips focal length that is already given to us which is 2 plus 2 .0 centimeter so in order to find s o e object distance from this i piece we use the lens equation again 1 by s -i -e plus 1 by s -o -e is equal to 1 by f -e.

04:06 Plugging in all the known values here this is 1 by minus 25 plus 1 by s -o -e this is missing we have to find it 1 by 2 .0 so 1 by s -o -e will come out to be 1 by 2 plus 1 by 25...

Question

A researcher uses a microscope with a convex lens to view a sample. The distance from the sample to the lens is 5 cm, and the distance from the lens to the retina is 20 cm. If the distance from the sample to the lens increases by 15 cm, the image is now focused:

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