a river 4miles wide is flowing at a rate of 2miles . the minimum time taken by a boat to cross the river with a speed 4 miles per hour in still water is approximately
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Step 1
Given: Velocity of the river, $v_r = 2$ mph Speed of the boat in still water, $v_b = 4$ mph Net velocity, $v_n = \sqrt{v_r^2 + v_b^2}$ $v_n = \sqrt{2^2 + 4^2}$ $v_n = \sqrt{4 + 16}$ $v_n = \sqrt{20}$ $v_n = 2\sqrt{5}$ mph ** Show more…
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