A silver nitrate solution contains 14.77 g of primary-standard AgNO 3 in 1.00 L. What volume of this solution will be needed to react with 0.1799 g of Na 2 CrO 4 ?
Added by Samet G.
Step 1
First, we need to find the moles of AgNO3 in the solution. Moles of AgNO3 = mass of AgNO3 / molar mass of AgNO3 Moles of AgNO3 = 14.77 g / (107.87 g/mol + 14.01 g/mol + 3 * 16.00 g/mol) Moles of AgNO3 = 14.77 g / 169.87 g/mol Moles of AgNO3 = 0.08697 mol Show more…
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