A small flashlight bulb provides a resistance of 6.0 Ω (Ohms) to the 400. mA current that runs through it. Determine the voltage of the battery in the flashlight. 2.4 V 4.6 V 6.4 V 15 V
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Step 1
0 Ω and the current (I) running through it is 400 mA (0.4 A). We need to find the voltage (V) of the battery. We can use Ohm's Law to solve this problem. Ohm's Law states that V = I × R. Now, we can plug in the values we know: Show more…
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