A thin rod of length 12.0 cm with a nonuniform linear charge density, $\lambda = c(x + 4)$, rests along the x-axis as shown in the figure. Evaluate the electric potential at a point P if $d = L/4$ and $c = 5.0$ pC/m$^2$.
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First, let's find the charge density at point P. The charge density is given by c(x + 4), where x is the distance from the left end of the rod. At point P, x = d = L/4. So the charge density at point P is c(d + 4) = c(L/4 + 4). Show more…
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