A Wire that is 48 cm long is shown below A) find a function that gives the total area $A(x)$ enclosed by the two squares (in square cm) in terms of $x$. B) Find the side length $x$ that minimizes the total area of the two squares. C) What is the minimum area enclosed by the two squares?
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The total length of the wire is 48 cm. The perimeter of two squares is $4x + 4(48-2x) = 4x + 192 - 8x = 192 - 4x$. Since the total length of the wire is 48 cm, we have $4x + 4(24-x) = 48$. This simplifies to $4x + 96 - 4x = 48$, which is always true. Let $x$ be Show more…
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