Question

Find the following. $f(x) = \sqrt{x^2 - 16}$, $g(x) = \frac{x^2}{x^2 + 1}$ (a) $(f + g)(x) = $ (b) $(f - g)(x) = $ (c) $(fg)(x) = $ (d) $(f/g)(x) = $ What is the domain of $f/g$? (Enter your answer using int

          Find the following.
$f(x) = \sqrt{x^2 - 16}$,	$g(x) = \frac{x^2}{x^2 + 1}$
(a) $(f + g)(x) = $
(b) $(f - g)(x) = $
(c) $(fg)(x) = $
(d) $(f/g)(x) = $
What is the domain of $f/g$? (Enter your answer using int

Find the following.
f(x) = √(x^2 - 16), g(x) = (x^2)/(x^2 + 1)
(a) (f + g)(x) =
(b) (f - g)(x) =
(c) (fg)(x) =
(d) (f/g)(x) =
What is the domain of f/g? (Enter your answer using int

Added by Stephen O.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Julian Wong

Step 1

However, we need to check if there are any values of x that make the denominator of (f/g)(x) equal to zero, which would make the function undefined. Setting the denominator equal to zero, we get x^2 + 1 = 0, which has no real solutions. Show more…

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Find the following: f(x) = âˆš(x^2 + 16), g(x) = x^2 + 1 (a) (f + g)(x) (b) (f - g)(x) (c) (f * g)(x) (d) (f / g)(x) What is the domain of (f/g)? (Enter your answer using interval notation)