Add. Simplify, if possible. (7)/(w^(2) 6w 9) (5)/(w^(2)-9) Add. Simplify, if possible. $$ \frac{7}{w^2+6w+9} + \frac{5}{w^2-9} $$
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The first denominator is a perfect square trinomial: $w^2+6w+9 = (w+3)^2$. The second denominator is a difference of squares: $w^2-9 = (w-3)(w+3)$. So the expression becomes: $$ \frac{7}{(w+3)^2} + \frac{5}{(w-3)(w+3)} $$ Show more…
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