An enzyme is used to produce a compound used in manufacture of sunscreen lotion. $v_{max}$ for the enzyme is 2.5 mmol m$^{-3}$s$^{-1}$; $K_m$ is 8.9 mM. The initial concentration of substrate is 12 mM. Plot the time required for batch reaction as a function of substrate conversion.
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5 \, \text{mmol m}^{-3} \text{s}^{-1} \) - \( K_m = 8.9 \, \text{mM} \) - Initial substrate concentration, \( [S_0] = 12 \, \text{mM} \) Show more…
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An enzyme is used to convert substrate to a commercial product in a 1600-litre batch reactor. Vmax for the enzyme is 0.9 g l-1 h-1; Km is 1.5 g l-1. Substrate concentration at the start of the reaction is 3 g l-1. Estimate time required for 90% conversion of substrate. Sf = 10% of S0 = 0.3 g/l t = 6.84 h
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Enzyme $\mathrm{E}$ catalyzes the transformation of reactant $\mathrm{A}$ to product $\mathrm{R}$ as follows: $$\mathrm{A} \stackrel{\text { enzyme }}{\longrightarrow} \mathrm{R}, \quad-r_{\mathrm{A}}=\frac{200 C_{\mathrm{A}} C_{\mathrm{E} 0}}{2+C_{\mathrm{A}}} \frac{\mathrm{mol}}{\text { liter } \cdot \mathrm{min}}$$ If we introduce enzyme $\left(C_{\mathrm{E} 0}=0.001 \mathrm{mol} / \text { liter }\right)$ and reactant $\left(C_{\mathrm{A} 0}=10\right.$ mol/liter) into a batch reactor and let the reaction proceed, find the time needed for the concentration of reactant to drop to 0.025 mol/liter. Note that the concentration of enzyme remains unchanged during the reaction.
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