00:01
For this question, if x2 is greater than x1, then the middle spring is extended and the tension that is given as k times x2 minus x1 will act in favor of acceleration.
00:53
The acceleration is represented as x1 like this.
00:58
This is acceleration, but it will be against the acceleration x2.
01:04
It will be against acceleration x2.
01:18
So if we represent it by the diagram, it can be represented as this is the surface, this is the body that we are talking about, and this is the tension that is k times x2 minus x1.
01:35
And the force is acting in opposite direction that is kx1, kx1.
01:48
Here this is x1.
01:50
And in another case, we have the same object and in this direction it is 2kx2 and the tension will be k times x2 minus x1.
02:10
This is x2.
02:11
So for this question, we have to write the equations of motion.
02:17
If we move further, then thus we can write this equation of motion of the two masses.
02:44
So the net force that is m into acceleration for first object that is mx1 will be equal to the sum of forces that is kx1 plus tension that is k times x2 minus x1...