Question

40. What is the output of the following code? interface calculate { void cal (int item); } class display implements calculate { int x; public void cal (int item) { x = item * item; } } class interfaces { public static void main(String args[]) { display arr = new display; arr.x = 0; arr.cal(2); System.out.print(arr.x); } } a) 0 b) 2 c) 4 d) compile error e) None of the mentioned

          40. What is the output of the following code?
interface calculate {
void cal (int item);
}
class display implements calculate {
int x;
public void cal (int item) {
x = item * item;
}
}
class interfaces {
public static void main(String args[]) {
display arr = new display;
arr.x = 0;
arr.cal(2);
System.out.print(arr.x);
}
}
a) 0
b) 2
c) 4
d) compile error
e) None of the mentioned

40. What is the output of the following code?
interface calculate
void cal (int item);

class display implements calculate
int x;
public void cal (int item)
x = item * item;

class interfaces
public static void main(String args[])
display arr = new display;
arr.x = 0;
arr.cal(2);
System.out.print(arr.x);

a) 0
b) 2
c) 4
d) compile error
e) None of the mentioned

Added by Derrick B.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert Reynald Oliveria

Step 1

We have an interface called "calculate" with a method declaration "void cal(int item)", a class "display" that implements this interface, and a class "interfaces" with the main method. Show more…

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40. What is the output of the following code? interface calculate { void cal(int item); } class display implements calculate { int x; public void cal(int item) { x = item * item; } } class interfaces { public static void main(String args[]) { display arr = new display(); arr.x = 0; arr.cal(2); System.out.print(arr.x); } } a) 0 b) 2 c) 4 d) compile error e) None of the mentioned