Question

Given parallelogram ABCD, BE = (2x + 3y) cm, DE = 12 cm AE = (4x + 3y) cm, and CE = 18 cm Solve for the values of x and y. Solution: Note that BE = ED and AE = EC (since diagonals bisect each other), thus, (1) AE = EC = 4x + 3y = 18 (2) BE = ED = 2x + 3y = 12 Simultaneously, by subtracting equation (2) from equation (1), we have, 2x = 6 x = 3 Solve for y: 2x + 3y = 12 2(3) + 3y = 12 Why? 3y = 6 y = 2 Use the figure item 8. Suppose BE = x cm, DE = (3y) cm, AE = (x + y) cm, and CE = 12 cm. Solve for the values of x and y.

          Given parallelogram ABCD,
BE = (2x + 3y) cm, DE = 12 cm
AE = (4x + 3y) cm, and
CE = 18 cm Solve for the
values of x and y.
Solution: Note that BE = ED and AE = EC
(since diagonals bisect each other), thus,
(1) AE = EC = 4x + 3y = 18
(2) BE = ED = 2x + 3y = 12
Simultaneously, by subtracting equation (2) from
equation (1), we have,
2x = 6
x = 3
Solve for y: 2x + 3y = 12
2(3) + 3y = 12 Why?
3y = 6
y = 2
Use the figure item 8. Suppose
BE = x cm, DE = (3y) cm, AE = (x + y)
cm, and CE = 12 cm. Solve for the
values of x and y.

Given parallelogram ABCD,
BE = (2x + 3y) cm, DE = 12 cm
AE = (4x + 3y) cm, and
CE = 18 cm Solve for the
values of x and y.
Solution: Note that BE = ED and AE = EC
(since diagonals bisect each other), thus,
(1) AE = EC = 4x + 3y = 18
(2) BE = ED = 2x + 3y = 12
Simultaneously, by subtracting equation (2) from
equation (1), we have,
2x = 6
x = 3
Solve for y: 2x + 3y = 12
2(3) + 3y = 12 Why?
3y = 6
y = 2
Use the figure item 8. Suppose
BE = x cm, DE = (3y) cm, AE = (x + y)
cm, and CE = 12 cm. Solve for the
values of x and y.

Added by Elizabeth C.

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