00:01
In this question, we are given the following data set which consists of the integers 1, 2, 3, 5 and 9.
00:10
So in the first part of the question, we are asked if the digits are not repeated, if the digits are not repeated, then 2 digit number can be formed in, then the 2 digits numbers can be formed, can be, formed in, so we have total of five numbers out of which two digit numbers can be formed in five p2 ways.
00:48
So this is equal to 20 ways and three digit number can be formed in three digits, three digits number can be formed can be formed in five p3 ways which is equal to 60 ways.
01:12
So, so so between these 63 digit numbers, 4 times 3 is equal to 12.
01:20
Number will be greater than, number will be greater than 900.
01:25
Hundreds place as 9.
01:29
Hundreds place as 9.
01:33
Therefore we have 20 plus 16 minus 12 is equal to 68 numbers between, is equal to 68 numbers, between 10 and 900 can be formed if the digits are not repeated.
01:50
Between 10 and 900 can be formed if the numbers are not repeated...