Assume that you have a sample of n₁ = 8, with the sample mean X₁ = 43, and a sample standard deviation of S₁ = 4,
and you have an independent sample of n₂ = 12 from another population with a sample mean of X2 = 36, and the
sample standard deviation S₂ = 8. Construct a 99% confidence interval estimate of the population mean difference
between µ₁ and µ₂. Assume that the two population variances are equal.
$$ \square \leq \mu_1 - \mu_2 \leq \square $$
(Round to two decimal places as needed.)