Attempt 1: 5 attempts remaining. Consider the equation $$\frac{2x-7}{x} = \frac{x-2}{5}$$. Step 1: Write the quadratic equation equivalent to the above equation. The coefficient of $$x^2$$ must be a positive number. Quadratic Equation: $$= 0$$ Step 2: Now, solve for $$x$$. Enter the solutions as a comma-separated list. If there are no real solutions, enter "none". $$x =$$ Submit answer Next item
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To eliminate the denominators, multiply both sides of the equation by $$5x$$ (assuming $$x \neq 0$$). $$5x \left(\frac{2x-7}{x}\right) = 5x \left(\frac{x-2}{5}\right)$$ $$5(2x-7) = x(x-2)$$ Show more…
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To see how to solve an equation that involves the absolute value of a quadratic polynomial, such as $\left|x^{2}-x\right|=6,$ work in order. Write an equation stating that $x^{2}-x$ is equal to the negative value found in Exercise $83,$ and solve it using the quadratic formula. (Hint: The solutions are not real numbers.)
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To see how to solve an equation that involves the absolute value of a quadratic polynomial, such as $\left|x^{2}-x\right|=6$ Write an equation stating that $x^{2}-x$ is equal to the negative value found in Exercise $83,$ and solve it using the quadratic formula. (Hint: The solutions are not real numbers.)
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