b) From the ideal gas law, if the temperature doesn't change, the pressure is directly proportional to the density. Thus if P_(0) and
ho _(0) are the values of pressure and density at sea level, then (P)/(P_(0))=(
ho )/(
ho _(0)). Use this to integrate the expression for dP from a) to obtain an expression for pressure P as a function of height z. Defining z_(0)=(P_(0))/(
ho _(0)(g)), where z_(0) is called the scale height, your final expression should be P=P_(0)e^(-((z)/(z_(0)))). That is, pressure decreases exponentially with height. Show all steps systematically. Use an extra sheet to complete your work.
(p)/(p_(0))=(
ho )/(
ho _(0))
dP=-
ho gdz
dP=((P)/(P_(0))*
ho _(0))gdz
proportional to the density. Thus if Po and po are the values of pressure and density at sea level, then P/Po =- p/po. Use this to integrate the expression for dP from a) to obtain an expression for pressure P as a function of height z. Defining zo = Po/(pog), where zo is called the scale height, your final expression should be P =- Po e-(z/zo). That is, pressure decreases exponentially with height. Show all steps systematically. Use an extra sheet to complete your work. P 2P6S=dP P. & 2p6(3)-p