00:01
We are asked to find the heat of formation of benzene given the values right here in kilojoules per mole.
00:12
And this will be co2 for combustion.
00:16
This will be h2o.
00:20
So first of all, i would like to write the combustion reaction and that's negative 3267 plus o2 yields co2 plus h2o.
00:48
This will be 36 and let me check here.
01:19
I'm just going to figure this out.
01:47
There's kenny ade.
01:51
So i'm going to go 2, 15, 12, and 6.
02:16
And i'm going to divide each of these by 2.
02:22
Okay.
02:25
And my heat of combustion, which was given, will equal the sum of my delta h of my products minus the sum of my delta h of my reactants.
02:41
So this will equal negative 3267 equals 6 times negative 394 plus 3 times negative 286 minus x plus 15 times zero.
03:19
Okay.
03:20
Let me do this now.
03:21
So i've got negative 3267 equals 6 times negative 394 plus parentheses 3 times negative 286.
03:35
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