(c) He2 bond order stability: stable unstable
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The bond order is calculated as follows: Bond order = (Number of bonding electrons - Number of antibonding electrons) / 2 For helium (He), there are 2 electrons in the 1s orbital. When two helium atoms come together to form He2, these 4 electrons are distributed Show more…
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Bond order normally gives idea of stability of a molecular species. All the molecules viz. $\mathrm{H}_{2}, \mathrm{Li}_{2}$ and $\mathrm{B}_{2}$ have the same bond order yet they are not equally stable. Their stability order is [Main Online April 22, 2013] (a) $\mathrm{H}_{2}>\mathrm{B}_{2}>\mathrm{Li}_{2}$ (b) $\mathrm{Li}_{2}>\mathrm{H}_{2}>\mathrm{B}_{2}$ (c) $\mathrm{Li}_{2}>\mathrm{B}_{2}>\mathrm{H}_{2}$ (d) $\mathrm{B}_{2}>\mathrm{H}_{2}>\mathrm{Li}_{2}$
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The correct order of stability for these compounds (a) $2>3>1$ (b) $3>2>1$ (c) $1>2>3$ (d) $3>1>2$
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