[C] Reduce the division where z = 4+ 3i, to the form a +bi, 0,6 € R: (Hint:The ensier is @ special type of compler number: )
Added by James F.
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First, we need to find the conjugate of z, which is z* = 4 - 3i. Show more…
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(d) If Z1 = 1-3i, Z2 = -2 + 5i, and Z3 = -3 - 4i, determine in the form a + bi the following: (i) Z1Z2 (ii) Z1/Z2 (iii) Z1Z2/(Z1+Z2) (iv) Z1Z2Z3
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(a) z = 6cis(̀̑/4) Enter the real part: Enter the imaginary part: (b) z = 4cis(̀̑/6) Enter the real part: Enter the imaginary part: (c) z = cis(-̀̑/2) / 3cis(̀̑/3) Enter the real part: Enter the imaginary part:
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a. Express (2+3i)/(i(4-5i)) + 2/i in the form a + ib. b. If z = (2+i)/(1-i), find the real and imaginary parts of the complex number z + 1/z c. Prove that 1+i is a root of z^5-6z^4+8z^3+4z^2-20z+16. Find the other roots of the equation. d. Express the following complex numbers in polar form: i. z1 = -1+i*sqrt(3) ii. z2 = -1-i*sqrt(3) iii. z3 = -1+i Hence, find the value of (z1^6 * z2^6) / z3^8
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